10-2(2x+5)=3x-(4+6x)

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Solution for 10-2(2x+5)=3x-(4+6x) equation: 



10-2(2x+5)=3x-(4+6x)

We move all terms to the left:

10-2(2x+5)-(3x-(4+6x))=0

We add all the numbers together, and all the variables

-2(2x+5)-(3x-(6x+4))+10=0

We multiply parentheses

-4x-(3x-(6x+4))-10+10=0



We calculate terms in parentheses: -(3x-(6x+4)), so:

3x-(6x+4)

We get rid of parentheses

3x-6x-4

We add all the numbers together, and all the variables

-3x-4

Back to the equation:

-(-3x-4)



We add all the numbers together, and all the variables

-4x-(-3x-4)=0

We get rid of parentheses

-4x+3x+4=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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