10-2(2x-3)=2(x+1)-1

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Solution for 10-2(2x-3)=2(x+1)-1 equation: 



10-2(2x-3)=2(x+1)-1

We move all terms to the left:

10-2(2x-3)-(2(x+1)-1)=0

We multiply parentheses

-4x-(2(x+1)-1)+6+10=0



We calculate terms in parentheses: -(2(x+1)-1), so:

2(x+1)-1

We multiply parentheses

2x+2-1

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-4x-(2x+1)+16=0

We get rid of parentheses

-4x-2x-1+16=0

We add all the numbers together, and all the variables

-6x+15=0

We move all terms containing x to the left, all other terms to the right

-6x=-15

x=-15/-6

x=2+1/2

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