10-2(2x-4)+3x=16

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Solution for 10-2(2x-4)+3x=16 equation: 



10-2(2x-4)+3x=16

We move all terms to the left:

10-2(2x-4)+3x-(16)=0

We add all the numbers together, and all the variables

3x-2(2x-4)-6=0

We multiply parentheses

3x-4x+8-6=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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