10-2(3x+1)=5(3x+4)

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Solution for 10-2(3x+1)=5(3x+4) equation: 



10-2(3x+1)=5(3x+4)

We move all terms to the left:

10-2(3x+1)-(5(3x+4))=0

We multiply parentheses

-6x-(5(3x+4))-2+10=0



We calculate terms in parentheses: -(5(3x+4)), so:

5(3x+4)

We multiply parentheses

15x+20

Back to the equation:

-(15x+20)



We add all the numbers together, and all the variables

-6x-(15x+20)+8=0

We get rid of parentheses

-6x-15x-20+8=0

We add all the numbers together, and all the variables

-21x-12=0

We move all terms containing x to the left, all other terms to the right

-21x=12

x=12/-21

x=-4/7

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