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10-2(3x-4)+4(x-5)=x-5(x+4)+2
We move all terms to the left:
10-2(3x-4)+4(x-5)-(x-5(x+4)+2)=0
We multiply parentheses
-6x+4x-(x-5(x+4)+2)+8-20+10=0
We calculate terms in parentheses: -(x-5(x+4)+2), so:We add all the numbers together, and all the variables
x-5(x+4)+2
We multiply parentheses
x-5x-20+2
We add all the numbers together, and all the variables
-4x-18
Back to the equation:
-(-4x-18)
-2x-(-4x-18)-2=0
We get rid of parentheses
-2x+4x+18-2=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8
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