10-2(3x-4)=4(x+1)-6

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Solution for 10-2(3x-4)=4(x+1)-6 equation: 



10-2(3x-4)=4(x+1)-6

We move all terms to the left:

10-2(3x-4)-(4(x+1)-6)=0

We multiply parentheses

-6x-(4(x+1)-6)+8+10=0



We calculate terms in parentheses: -(4(x+1)-6), so:

4(x+1)-6

We multiply parentheses

4x+4-6

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

-6x-(4x-2)+18=0

We get rid of parentheses

-6x-4x+2+18=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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