10-2(3x-4)=4x-12

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Solution for 10-2(3x-4)=4x-12 equation: 



10-2(3x-4)=4x-12

We move all terms to the left:

10-2(3x-4)-(4x-12)=0

We multiply parentheses

-6x-(4x-12)+8+10=0

We get rid of parentheses

-6x-4x+12+8+10=0

We add all the numbers together, and all the variables

-10x+30=0

We move all terms containing x to the left, all other terms to the right

-10x=-30

x=-30/-10

x=+3

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