10-2(4+3x)=-2(1-3x)

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Solution for 10-2(4+3x)=-2(1-3x) equation: 



10-2(4+3x)=-2(1-3x)

We move all terms to the left:

10-2(4+3x)-(-2(1-3x))=0

We add all the numbers together, and all the variables

-2(3x+4)-(-2(-3x+1))+10=0

We multiply parentheses

-6x-(-2(-3x+1))-8+10=0



We calculate terms in parentheses: -(-2(-3x+1)), so:

-2(-3x+1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

-6x-(6x-2)+2=0

We get rid of parentheses

-6x-6x+2+2=0

We add all the numbers together, and all the variables

-12x+4=0

We move all terms containing x to the left, all other terms to the right

-12x=-4

x=-4/-12

x=1/3

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