10-2(n-5)=10-4n

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Solution for 10-2(n-5)=10-4n equation: 



10-2(n-5)=10-4n

We move all terms to the left:

10-2(n-5)-(10-4n)=0

We add all the numbers together, and all the variables

-2(n-5)-(-4n+10)+10=0

We multiply parentheses

-2n-(-4n+10)+10+10=0

We get rid of parentheses

-2n+4n-10+10+10=0

We add all the numbers together, and all the variables

2n+10=0

We move all terms containing n to the left, all other terms to the right

2n=-10

n=-10/2

n=-5

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