10-2(x+3)=(x-2)-5x+10

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Solution for 10-2(x+3)=(x-2)-5x+10 equation: 



10-2(x+3)=(x-2)-5x+10

We move all terms to the left:

10-2(x+3)-((x-2)-5x+10)=0

We multiply parentheses

-2x-((x-2)-5x+10)-6+10=0



We calculate terms in parentheses: -((x-2)-5x+10), so:

(x-2)-5x+10

We add all the numbers together, and all the variables

-5x+(x-2)+10

We get rid of parentheses

-5x+x-2+10

We add all the numbers together, and all the variables

-4x+8

Back to the equation:

-(-4x+8)



We add all the numbers together, and all the variables

-2x-(-4x+8)+4=0

We get rid of parentheses

-2x+4x-8+4=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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