10-2(x+3)=-6

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Solution for 10-2(x+3)=-6 equation: 



10-2(x+3)=-6

We move all terms to the left:

10-2(x+3)-(-6)=0

We add all the numbers together, and all the variables

-2(x+3)+16=0

We multiply parentheses

-2x-6+16=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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