10-2(x+3)=4(x-1)-8

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Solution for 10-2(x+3)=4(x-1)-8 equation: 



10-2(x+3)=4(x-1)-8

We move all terms to the left:

10-2(x+3)-(4(x-1)-8)=0

We multiply parentheses

-2x-(4(x-1)-8)-6+10=0



We calculate terms in parentheses: -(4(x-1)-8), so:

4(x-1)-8

We multiply parentheses

4x-4-8

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

-2x-(4x-12)+4=0

We get rid of parentheses

-2x-4x+12+4=0

We add all the numbers together, and all the variables

-6x+16=0

We move all terms containing x to the left, all other terms to the right

-6x=-16

x=-16/-6

x=2+2/3

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