10-2(x+3)=7(x-2)+9

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Solution for 10-2(x+3)=7(x-2)+9 equation: 



10-2(x+3)=7(x-2)+9

We move all terms to the left:

10-2(x+3)-(7(x-2)+9)=0

We multiply parentheses

-2x-(7(x-2)+9)-6+10=0



We calculate terms in parentheses: -(7(x-2)+9), so:

7(x-2)+9

We multiply parentheses

7x-14+9

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We add all the numbers together, and all the variables

-2x-(7x-5)+4=0

We get rid of parentheses

-2x-7x+5+4=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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