10-2(x-4)=3(x+3)+2

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Solution for 10-2(x-4)=3(x+3)+2 equation: 



10-2(x-4)=3(x+3)+2

We move all terms to the left:

10-2(x-4)-(3(x+3)+2)=0

We multiply parentheses

-2x-(3(x+3)+2)+8+10=0



We calculate terms in parentheses: -(3(x+3)+2), so:

3(x+3)+2

We multiply parentheses

3x+9+2

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

-2x-(3x+11)+18=0

We get rid of parentheses

-2x-3x-11+18=0

We add all the numbers together, and all the variables

-5x+7=0

We move all terms containing x to the left, all other terms to the right

-5x=-7

x=-7/-5

x=1+2/5

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