10-3(1+11b)=8-4(1+8b)

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Solution for 10-3(1+11b)=8-4(1+8b) equation: 



10-3(1+11b)=8-4(1+8b)

We move all terms to the left:

10-3(1+11b)-(8-4(1+8b))=0

We add all the numbers together, and all the variables

-3(11b+1)-(8-4(8b+1))+10=0

We multiply parentheses

-33b-(8-4(8b+1))-3+10=0



We calculate terms in parentheses: -(8-4(8b+1)), so:

8-4(8b+1)

determiningTheFunctionDomain
-4(8b+1)+8

We multiply parentheses

-32b-4+8

We add all the numbers together, and all the variables

-32b+4

Back to the equation:

-(-32b+4)



We add all the numbers together, and all the variables

-33b-(-32b+4)+7=0

We get rid of parentheses

-33b+32b-4+7=0

We add all the numbers together, and all the variables

-1b+3=0

We move all terms containing b to the left, all other terms to the right

-b=-3

b=-3/-1

b=+3

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