10-3(2+t)=28

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Solution for 10-3(2+t)=28 equation: 



10-3(2+t)=28

We move all terms to the left:

10-3(2+t)-(28)=0

We add all the numbers together, and all the variables

-3(t+2)+10-28=0

We add all the numbers together, and all the variables

-3(t+2)-18=0

We multiply parentheses

-3t-6-18=0

We add all the numbers together, and all the variables

-3t-24=0

We move all terms containing t to the left, all other terms to the right

-3t=24

t=24/-3

t=-8

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