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10-3(2-4x)=3(x+2)
We move all terms to the left:
10-3(2-4x)-(3(x+2))=0
We add all the numbers together, and all the variables
-3(-4x+2)-(3(x+2))+10=0
We multiply parentheses
12x-(3(x+2))-6+10=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
12x-(3x+6)+4=0
We get rid of parentheses
12x-3x-6+4=0
We add all the numbers together, and all the variables
9x-2=0
We move all terms containing x to the left, all other terms to the right
9x=2
x=2/9
x=2/9
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