10-3(2c-5)=2-(4c+7)

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Solution for 10-3(2c-5)=2-(4c+7) equation:


Simplifying
10 + -3(2c + -5) = 2 + -1(4c + 7)

Reorder the terms:
10 + -3(-5 + 2c) = 2 + -1(4c + 7)
10 + (-5 * -3 + 2c * -3) = 2 + -1(4c + 7)
10 + (15 + -6c) = 2 + -1(4c + 7)

Combine like terms: 10 + 15 = 25
25 + -6c = 2 + -1(4c + 7)

Reorder the terms:
25 + -6c = 2 + -1(7 + 4c)
25 + -6c = 2 + (7 * -1 + 4c * -1)
25 + -6c = 2 + (-7 + -4c)

Combine like terms: 2 + -7 = -5
25 + -6c = -5 + -4c

Solving
25 + -6c = -5 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
25 + -6c + 4c = -5 + -4c + 4c

Combine like terms: -6c + 4c = -2c
25 + -2c = -5 + -4c + 4c

Combine like terms: -4c + 4c = 0
25 + -2c = -5 + 0
25 + -2c = -5

Add '-25' to each side of the equation.
25 + -25 + -2c = -5 + -25

Combine like terms: 25 + -25 = 0
0 + -2c = -5 + -25
-2c = -5 + -25

Combine like terms: -5 + -25 = -30
-2c = -30

Divide each side by '-2'.
c = 15

Simplifying
c = 15

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