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10-3(2x+5)=2(2x-5)
We move all terms to the left:
10-3(2x+5)-(2(2x-5))=0
We multiply parentheses
-6x-(2(2x-5))-15+10=0
We calculate terms in parentheses: -(2(2x-5)), so:We add all the numbers together, and all the variables
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
-6x-(4x-10)-5=0
We get rid of parentheses
-6x-4x+10-5=0
We add all the numbers together, and all the variables
-10x+5=0
We move all terms containing x to the left, all other terms to the right
-10x=-5
x=-5/-10
x=1/2
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