10-3(4x-5)=7x+12

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Solution for 10-3(4x-5)=7x+12 equation: 



10-3(4x-5)=7x+12

We move all terms to the left:

10-3(4x-5)-(7x+12)=0

We multiply parentheses

-12x-(7x+12)+15+10=0

We get rid of parentheses

-12x-7x-12+15+10=0

We add all the numbers together, and all the variables

-19x+13=0

We move all terms containing x to the left, all other terms to the right

-19x=-13

x=-13/-19

x=13/19

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