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10-3(x+2)=2(2x+4)+3
We move all terms to the left:
10-3(x+2)-(2(2x+4)+3)=0
We multiply parentheses
-3x-(2(2x+4)+3)-6+10=0
We calculate terms in parentheses: -(2(2x+4)+3), so:We add all the numbers together, and all the variables
2(2x+4)+3
We multiply parentheses
4x+8+3
We add all the numbers together, and all the variables
4x+11
Back to the equation:
-(4x+11)
-3x-(4x+11)+4=0
We get rid of parentheses
-3x-4x-11+4=0
We add all the numbers together, and all the variables
-7x-7=0
We move all terms containing x to the left, all other terms to the right
-7x=7
x=7/-7
x=-1
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