10-3(x+2)=2(x+1)-3

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Solution for 10-3(x+2)=2(x+1)-3 equation: 



10-3(x+2)=2(x+1)-3

We move all terms to the left:

10-3(x+2)-(2(x+1)-3)=0

We multiply parentheses

-3x-(2(x+1)-3)-6+10=0



We calculate terms in parentheses: -(2(x+1)-3), so:

2(x+1)-3

We multiply parentheses

2x+2-3

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

-3x-(2x-1)+4=0

We get rid of parentheses

-3x-2x+1+4=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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