10-3(x+2)=32-6(3x-2)

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Solution for 10-3(x+2)=32-6(3x-2) equation: 



10-3(x+2)=32-6(3x-2)

We move all terms to the left:

10-3(x+2)-(32-6(3x-2))=0

We multiply parentheses

-3x-(32-6(3x-2))-6+10=0



We calculate terms in parentheses: -(32-6(3x-2)), so:

32-6(3x-2)

determiningTheFunctionDomain
-6(3x-2)+32

We multiply parentheses

-18x+12+32

We add all the numbers together, and all the variables

-18x+44

Back to the equation:

-(-18x+44)



We add all the numbers together, and all the variables

-3x-(-18x+44)+4=0

We get rid of parentheses

-3x+18x-44+4=0

We add all the numbers together, and all the variables

15x-40=0

We move all terms containing x to the left, all other terms to the right

15x=40

x=40/15

x=2+2/3

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