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10-3(x+5)=1/4(4x-32)
We move all terms to the left:
10-3(x+5)-(1/4(4x-32))=0
Domain of the equation: 4(4x-32))!=0We multiply parentheses
x∈R
-3x-(1/4(4x-32))-15+10=0
We multiply all the terms by the denominator
-3x*4(4x-32))-(1-15*4(4x-32))+10*4(4x-32))=0
We add all the numbers together, and all the variables
-3x*4(4x-32))-(1-15*4(4x-32))+10*4(4x=0
Wy multiply elements
-12x^2(4-240x^2(4=0
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