10-3(z=2)=9z+1

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Solution for 10-3(z=2)=9z+1 equation: 



10-3(z=2)=9z+1

We move all terms to the left:

10-3(z-(2))=0

We multiply parentheses

-3z+6+10=0

We add all the numbers together, and all the variables

-3z+16=0

We move all terms containing z to the left, all other terms to the right

-3z=-16

z=-16/-3

z=5+1/3

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