10-3b=-1+(b+2)

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Solution for 10-3b=-1+(b+2) equation: 



10-3b=-1+(b+2)

We move all terms to the left:

10-3b-(-1+(b+2))=0



We calculate terms in parentheses: -(-1+(b+2)), so:

-1+(b+2)

determiningTheFunctionDomain
(b+2)-1

We get rid of parentheses

b+2-1

We add all the numbers together, and all the variables

b+1

Back to the equation:

-(b+1)



We get rid of parentheses

-3b-b-1+10=0

We add all the numbers together, and all the variables

-4b+9=0

We move all terms containing b to the left, all other terms to the right

-4b=-9

b=-9/-4

b=2+1/4

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