10-3b=-5(b-5)+2b

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Solution for 10-3b=-5(b-5)+2b equation: 



10-3b=-5(b-5)+2b

We move all terms to the left:

10-3b-(-5(b-5)+2b)=0



We calculate terms in parentheses: -(-5(b-5)+2b), so:

-5(b-5)+2b

We add all the numbers together, and all the variables

2b-5(b-5)

We multiply parentheses

2b-5b+25

We add all the numbers together, and all the variables

-3b+25

Back to the equation:

-(-3b+25)



We get rid of parentheses

-3b+3b-25+10=0

We add all the numbers together, and all the variables

-15!=0

There is no solution for this equation

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