10-3x-1=7+3x2

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Solution for 10-3x-1=7+3x2 equation:



10-3x-1=7+3x^2
We move all terms to the left:
10-3x-1-(7+3x^2)=0
We add all the numbers together, and all the variables
-(7+3x^2)-3x+9=0
We get rid of parentheses
-3x^2-3x-7+9=0
We add all the numbers together, and all the variables
-3x^2-3x+2=0
a = -3; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-3)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*-3}=\frac{3-\sqrt{33}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*-3}=\frac{3+\sqrt{33}}{-6} $

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