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10-3x^2=16
We move all terms to the left:
10-3x^2-(16)=0
We add all the numbers together, and all the variables
-3x^2-6=0
a = -3; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-3)·(-6)
Δ = -72
Delta is less than zero, so there is no solution for the equation
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