10-4(x-8)=2(x+6)

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Solution for 10-4(x-8)=2(x+6) equation: 



10-4(x-8)=2(x+6)

We move all terms to the left:

10-4(x-8)-(2(x+6))=0

We multiply parentheses

-4x-(2(x+6))+32+10=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

-4x-(2x+12)+42=0

We get rid of parentheses

-4x-2x-12+42=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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