10-5(h+3)+50=3(h+4)-23

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Solution for 10-5(h+3)+50=3(h+4)-23 equation: 



10-5(h+3)+50=3(h+4)-23

We move all terms to the left:

10-5(h+3)+50-(3(h+4)-23)=0

We add all the numbers together, and all the variables

-5(h+3)-(3(h+4)-23)+60=0

We multiply parentheses

-5h-(3(h+4)-23)-15+60=0



We calculate terms in parentheses: -(3(h+4)-23), so:

3(h+4)-23

We multiply parentheses

3h+12-23

We add all the numbers together, and all the variables

3h-11

Back to the equation:

-(3h-11)



We add all the numbers together, and all the variables

-5h-(3h-11)+45=0

We get rid of parentheses

-5h-3h+11+45=0

We add all the numbers together, and all the variables

-8h+56=0

We move all terms containing h to the left, all other terms to the right

-8h=-56

h=-56/-8

h=+7

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