10-5(x+4)=12-7(x+2)

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Solution for 10-5(x+4)=12-7(x+2) equation: 



10-5(x+4)=12-7(x+2)

We move all terms to the left:

10-5(x+4)-(12-7(x+2))=0

We multiply parentheses

-5x-(12-7(x+2))-20+10=0



We calculate terms in parentheses: -(12-7(x+2)), so:

12-7(x+2)

determiningTheFunctionDomain
-7(x+2)+12

We multiply parentheses

-7x-14+12

We add all the numbers together, and all the variables

-7x-2

Back to the equation:

-(-7x-2)



We add all the numbers together, and all the variables

-5x-(-7x-2)-10=0

We get rid of parentheses

-5x+7x+2-10=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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