10-5(x-2)=7-3(2x-1)

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Solution for 10-5(x-2)=7-3(2x-1) equation:



10-5(x-2)=7-3(2x-1)
We move all terms to the left:
10-5(x-2)-(7-3(2x-1))=0
We multiply parentheses
-5x-(7-3(2x-1))+10+10=0
We calculate terms in parentheses: -(7-3(2x-1)), so:
7-3(2x-1)
determiningTheFunctionDomain -3(2x-1)+7
We multiply parentheses
-6x+3+7
We add all the numbers together, and all the variables
-6x+10
Back to the equation:
-(-6x+10)
We add all the numbers together, and all the variables
-5x-(-6x+10)+20=0
We get rid of parentheses
-5x+6x-10+20=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10

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