10-5(x-3)=4(3-2x)

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Solution for 10-5(x-3)=4(3-2x) equation:



10-5(x-3)=4(3-2x)
We move all terms to the left:
10-5(x-3)-(4(3-2x))=0
We add all the numbers together, and all the variables
-5(x-3)-(4(-2x+3))+10=0
We multiply parentheses
-5x-(4(-2x+3))+15+10=0
We calculate terms in parentheses: -(4(-2x+3)), so:
4(-2x+3)
We multiply parentheses
-8x+12
Back to the equation:
-(-8x+12)
We add all the numbers together, and all the variables
-5x-(-8x+12)+25=0
We get rid of parentheses
-5x+8x-12+25=0
We add all the numbers together, and all the variables
3x+13=0
We move all terms containing x to the left, all other terms to the right
3x=-13
x=-13/3
x=-4+1/3

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