10-5(x-3)=4(3-2x)

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Solution for 10-5(x-3)=4(3-2x) equation: 



10-5(x-3)=4(3-2x)

We move all terms to the left:

10-5(x-3)-(4(3-2x))=0

We add all the numbers together, and all the variables

-5(x-3)-(4(-2x+3))+10=0

We multiply parentheses

-5x-(4(-2x+3))+15+10=0



We calculate terms in parentheses: -(4(-2x+3)), so:

4(-2x+3)

We multiply parentheses

-8x+12

Back to the equation:

-(-8x+12)



We add all the numbers together, and all the variables

-5x-(-8x+12)+25=0

We get rid of parentheses

-5x+8x-12+25=0

We add all the numbers together, and all the variables

3x+13=0

We move all terms containing x to the left, all other terms to the right

3x=-13

x=-13/3

x=-4+1/3

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