10-5*(2-2x)+2*(x+4)=2*(2-3x)-4*(6-x)

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Solution for 10-5*(2-2x)+2*(x+4)=2*(2-3x)-4*(6-x) equation: 



10-5(2-2x)+2(x+4)=2(2-3x)-4(6-x)

We move all terms to the left:

10-5(2-2x)+2(x+4)-(2(2-3x)-4(6-x))=0

We add all the numbers together, and all the variables

-5(-2x+2)+2(x+4)-(2(-3x+2)-4(-1x+6))+10=0

We multiply parentheses

10x+2x-(2(-3x+2)-4(-1x+6))-10+8+10=0



We calculate terms in parentheses: -(2(-3x+2)-4(-1x+6)), so:

2(-3x+2)-4(-1x+6)

We multiply parentheses

-6x+4x+4-24

We add all the numbers together, and all the variables

-2x-20

Back to the equation:

-(-2x-20)



We add all the numbers together, and all the variables

12x-(-2x-20)+8=0

We get rid of parentheses

12x+2x+20+8=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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