10-5x=(20-10x)1/2

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Solution for 10-5x=(20-10x)1/2 equation: 


x in (-oo:+oo)

10-(5*x) = ((20-(10*x))^1)/2 // - ((20-(10*x))^1)/2

10-(((20-(10*x))^1)/2)-(5*x) = 0

10-((20-10*x)/2)-5*x = 0

(-1*(20-10*x))/2-5*x+10 = 0

(-1*(20-10*x))/2+(-5*2*x)/2+(2*10)/2 = 0

2*10-1*(20-10*x)-5*2*x = 0

20-20 = 0

0 = 0

0/2 = 0

0/2 = 0 // * 2

0 = 0

0 = 0

x należy do R

x in (-oo:+oo)

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