10-5x=3(x-4)-2(x+3)

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Solution for 10-5x=3(x-4)-2(x+3) equation: 



10-5x=3(x-4)-2(x+3)

We move all terms to the left:

10-5x-(3(x-4)-2(x+3))=0



We calculate terms in parentheses: -(3(x-4)-2(x+3)), so:

3(x-4)-2(x+3)

We multiply parentheses

3x-2x-12-6

We add all the numbers together, and all the variables

x-18

Back to the equation:

-(x-18)



We get rid of parentheses

-5x-x+18+10=0

We add all the numbers together, and all the variables

-6x+28=0

We move all terms containing x to the left, all other terms to the right

-6x=-28

x=-28/-6

x=4+2/3

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