10-6((2-3x)/5)=(3x+1)/2

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Solution for 10-6((2-3x)/5)=(3x+1)/2 equation: 


x in (-oo:+oo)

10-(6*((2-(3*x))/5)) = (3*x+1)/2 // - (3*x+1)/2

10-(6*((2-(3*x))/5))-((3*x+1)/2) = 0

(-6/5)*(2-3*x)-((3*x+1)/2)+10 = 0

(-1*(3*x+1))/2-6/5*(2-3*x)+10 = 0

(-6/5*2*(2-3*x))/2+(-1*(3*x+1))/2+(2*10)/2 = 0

2*10-6/5*2*(2-3*x)-1*(3*x+1) = 0

21/5*x-29/5+20 = 0

21/5*x+71/5 = 0

(21/5*x+71/5)/2 = 0

(21/5*x+71/5)/2 = 0 // * 2

21/5*x+71/5 = 0

21/5*x+71/5 = 0 // - 71/5

21/5*x = -71/5 // : 21/5

x = -71/5/21/5

x = -71/21

x = -71/21

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