10-6(8x-)=9x-(3+4x)

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Solution for 10-6(8x-)=9x-(3+4x) equation: 



10-6(8x-)=9x-(3+4x)

We move all terms to the left:

10-6(8x-)-(9x-(3+4x))=0

We add all the numbers together, and all the variables

-6(+8x)-(9x-(4x+3))+10=0

We multiply parentheses

-48x-(9x-(4x+3))+10=0



We calculate terms in parentheses: -(9x-(4x+3)), so:

9x-(4x+3)

We get rid of parentheses

9x-4x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

-48x-5x+3+10=0

We add all the numbers together, and all the variables

-53x+13=0

We move all terms containing x to the left, all other terms to the right

-53x=-13

x=-13/-53

x=13/53

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