10-6(8x-20)=9x-(3+4x)

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Solution for 10-6(8x-20)=9x-(3+4x) equation: 



10-6(8x-20)=9x-(3+4x)

We move all terms to the left:

10-6(8x-20)-(9x-(3+4x))=0

We add all the numbers together, and all the variables

-6(8x-20)-(9x-(4x+3))+10=0

We multiply parentheses

-48x-(9x-(4x+3))+120+10=0



We calculate terms in parentheses: -(9x-(4x+3)), so:

9x-(4x+3)

We get rid of parentheses

9x-4x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We add all the numbers together, and all the variables

-48x-(5x-3)+130=0

We get rid of parentheses

-48x-5x+3+130=0

We add all the numbers together, and all the variables

-53x+133=0

We move all terms containing x to the left, all other terms to the right

-53x=-133

x=-133/-53

x=2+27/53

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