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10-6c=2(c-3)
We move all terms to the left:
10-6c-(2(c-3))=0
We calculate terms in parentheses: -(2(c-3)), so:We get rid of parentheses
2(c-3)
We multiply parentheses
2c-6
Back to the equation:
-(2c-6)
-6c-2c+6+10=0
We add all the numbers together, and all the variables
-8c+16=0
We move all terms containing c to the left, all other terms to the right
-8c=-16
c=-16/-8
c=+2
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