10-6c=2(c-3)

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Solution for 10-6c=2(c-3) equation: 



10-6c=2(c-3)

We move all terms to the left:

10-6c-(2(c-3))=0



We calculate terms in parentheses: -(2(c-3)), so:

2(c-3)

We multiply parentheses

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

-6c-2c+6+10=0

We add all the numbers together, and all the variables

-8c+16=0

We move all terms containing c to the left, all other terms to the right

-8c=-16

c=-16/-8

c=+2

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