10-6x+3=2(x-3)-45

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Solution for 10-6x+3=2(x-3)-45 equation: 



10-6x+3=2(x-3)-45

We move all terms to the left:

10-6x+3-(2(x-3)-45)=0

We add all the numbers together, and all the variables

-6x-(2(x-3)-45)+13=0



We calculate terms in parentheses: -(2(x-3)-45), so:

2(x-3)-45

We multiply parentheses

2x-6-45

We add all the numbers together, and all the variables

2x-51

Back to the equation:

-(2x-51)



We get rid of parentheses

-6x-2x+51+13=0

We add all the numbers together, and all the variables

-8x+64=0

We move all terms containing x to the left, all other terms to the right

-8x=-64

x=-64/-8

x=+8

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