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10-p=2/3p
We move all terms to the left:
10-p-(2/3p)=0
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
-p-(+2/3p)+10=0
We add all the numbers together, and all the variables
-1p-(+2/3p)+10=0
We get rid of parentheses
-1p-2/3p+10=0
We multiply all the terms by the denominator
-1p*3p+10*3p-2=0
Wy multiply elements
-3p^2+30p-2=0
a = -3; b = 30; c = -2;
Δ = b2-4ac
Δ = 302-4·(-3)·(-2)
Δ = 876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{876}=\sqrt{4*219}=\sqrt{4}*\sqrt{219}=2\sqrt{219}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{219}}{2*-3}=\frac{-30-2\sqrt{219}}{-6} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{219}}{2*-3}=\frac{-30+2\sqrt{219}}{-6} $
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