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10-x/12x=8/3x
We move all terms to the left:
10-x/12x-(8/3x)=0
Domain of the equation: 12x!=0
x!=0/12
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x/12x-(+8/3x)+10=0
We get rid of parentheses
-x/12x-8/3x+10=0
We calculate fractions
(-3x^2)/36x^2+(-96x)/36x^2+10=0
We multiply all the terms by the denominator
(-3x^2)+(-96x)+10*36x^2=0
Wy multiply elements
(-3x^2)+360x^2+(-96x)=0
We get rid of parentheses
-3x^2+360x^2-96x=0
We add all the numbers together, and all the variables
357x^2-96x=0
a = 357; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·357·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*357}=\frac{0}{714} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*357}=\frac{192}{714} =32/119 $
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