10/(2x-3)=7/(3x)

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Solution for 10/(2x-3)=7/(3x) equation:


D( x )

3*x = 0

2*x-3 = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in (-oo:0) U (0:3/2) U (3/2:+oo)

10/(2*x-3) = 7/(3*x) // - 7/(3*x)

10/(2*x-3)-(7/(3*x)) = 0

10/(2*x-3)+(-7/3)*x^-1 = 0

10/(2*x-3)-7/(3*x) = 0

(3*10*x)/(3*x*(2*x-3))+(-7*(2*x-3))/(3*x*(2*x-3)) = 0

3*10*x-7*(2*x-3) = 0

16*x+21 = 0

(16*x+21)/(3*x*(2*x-3)) = 0

(16*x+21)/(3*x*(2*x-3)) = 0 // * 3*x*(2*x-3)

16*x+21 = 0

16*x+21 = 0 // - 21

16*x = -21 // : 16

x = -21/16

x = -21/16

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