10/(8-2i)

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Solution for 10/(8-2i) equation: 


D( i )

8-(2*i) = 0

8-(2*i) = 0

8-(2*i) = 0

8-2*i = 0

8-2*i = 0 // - 8

-2*i = -8 // : -2

i = -8/(-2)

i = 4

i in (-oo:4) U (4:+oo)

10/(8-(2*i)) = 0

10/(8-2*i) = 0

10 = 0

i belongs to the empty set

i belongs to the empty set

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