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10/(x+3)-2/x=1
We move all terms to the left:
10/(x+3)-2/x-(1)=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
10x/(x^2+3x)+(-2x-6)/(x^2+3x)-1=0
We multiply all the terms by the denominator
10x+(-2x-6)-1*(x^2+3x)=0
We get rid of parentheses
10x-2x-1*(x^2+3x)-6=0
We add all the numbers together, and all the variables
8x-1*(x^2+3x)-6=0
We move all terms containing x to the left, all other terms to the right
8x-1*(x^2+3x)=6
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