10/12t-12=-60

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Solution for 10/12t-12=-60 equation: 



10/12t-12=-60

We move all terms to the left:

10/12t-12-(-60)=0



Domain of the equation: 12t!=0

t!=0/12

t!=0

t∈R



We add all the numbers together, and all the variables

10/12t+48=0

We multiply all the terms by the denominator


48*12t+10=0

Wy multiply elements

576t+10=0

We move all terms containing t to the left, all other terms to the right

576t=-10

t=-10/576

t=-5/288

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