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10/12x+3/4x=19/12
We move all terms to the left:
10/12x+3/4x-(19/12)=0
Domain of the equation: 12x!=0
x!=0/12
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
10/12x+3/4x-(+19/12)=0
We get rid of parentheses
10/12x+3/4x-19/12=0
We calculate fractions
40x/576x^2+432x/576x^2+(-76x)/576x^2=0
We multiply all the terms by the denominator
40x+432x+(-76x)=0
We add all the numbers together, and all the variables
472x+(-76x)=0
We get rid of parentheses
472x-76x=0
We add all the numbers together, and all the variables
396x=0
x=0/396
x=0
Równanie nie ma rozwiązania
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