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10/15x-3/15x=x-1
We move all terms to the left:
10/15x-3/15x-(x-1)=0
Domain of the equation: 15x!=0We get rid of parentheses
x!=0/15
x!=0
x∈R
10/15x-3/15x-x+1=0
We multiply all the terms by the denominator
-x*15x+1*15x+10-3=0
We add all the numbers together, and all the variables
-x*15x+1*15x+7=0
Wy multiply elements
-15x^2+15x+7=0
a = -15; b = 15; c = +7;
Δ = b2-4ac
Δ = 152-4·(-15)·7
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{645}}{2*-15}=\frac{-15-\sqrt{645}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{645}}{2*-15}=\frac{-15+\sqrt{645}}{-30} $
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